Flywheelapparatuslabreportdiscussion
Experiment:DeterminationofmomentofInertiaofaFlyWheelTheory:Theflywheelconsistsofaweightyrounddisc/massivewheelfixedwithastrongaxleprojectingoneitherside.Theaxleismountedonballbearingsontwofixedsupports.Thereisalittlepegontheaxle.blankcheckregisterpdfOneendofacordislooselyloopedaroundthepeg
anditsotherendcarriestheweight-hanger.Suppose,theangularvelocityofawheelisωanditsradiusr.Thenlinealvelocityofthewheelis,v=ωr.IfthemomentofinertiaofabodyisIandthewheelisrotatingaroundanaxle.Thenitsrotationalkineticenergy,E=½Iω2.Apparatus:Anironaxle,aheavywheel,someropes,amass,stopwatch,meter
scale,slidecalipers.Descriptionoftheapparatus:Theflywheelwassetasshownwiththeaxleoftheflywheelstraightorparallel.Apolystyrenetilewasplacedonthefloortoavoidthecollisionofthemassonthefloor.(1)Firstofall,letusmeasuretheradiusoftheaxlebyaslidecaliper.(2)Thenforthedeterminationofanumberofrotationamarkby
chalkisputontheaxleandaropeiswoundontheaxle.AttheotherendoftheropeamassmisfastenedandifitisdroppedfrompositionR,thewheelafterrotatingafewtimes,theweightwiththeropewillfalltopositionS.Thewheelmakesm1numberofrotationtotouchthepointSandtimeforthisdropisnotedfromthestopwatch.Nowthe
ropeisagainwoundontheaxleandthemassisfastenedontheotherendoftherope.FrompositionRthemassisallowedtofalltothegroundandassoonasittouchestheground,thestopwatchisstarted.Whentheaxlecomestorestthestopwealthisstopped.Totaltimeandthenumberofrotationofthewheelbeforeitcomestorestarenotedi.e.,
atotalnumberofrotation(n2)asnoted.Table1:radius(r)oftheaxleBTable2:DeterminationoftimeandnumberofrotationCalculation:Iftheaxistakestimetforn2numberofrotation,theaverageangularvelocity,ω2=(2πn2)/tTheaxleacquireszerovelocitywithuniformretardationfromangularvelocityω,soitsaverageangularvelocity,ω2=(ω
+0)/2=ω/2or,(2πn2)/t=ω/2or,ω=4πn2radS-1Then,I=(2mgh–mω2r2)/ω2(1+n1/n2)=…..large_print_word_search_for_seniors_printable.pdfg.cm2=…..Kg.m2Byinsertingthevalueofn2,ωcanbefoundout.Byincreasingthevaluesofm,ω,r,h,n1,n2andginanequation;themomentofinertiaoftheheavywheelcanbefound
out.Precautions:Intheaxle,aropeistobewoundedinsuchawaythatwhileunwindingfromthewheelitcaneasilydropontheground.Thereshouldbetheleastfrictionintheflywheel.Anumberofrotationnandtimetistobeunwiredcorrectly.Thelengthofthestringshouldbelessthantheheightofaxlefromthefloor.Height‘h’istobe
measuredfromthemarkontheaxle.‘h’istobemeasuredcorrectly.Thereshouldbenokinkinstringandstringshouldbethinandshouldbewoundevenly.Thestopwatchshouldbestartedjustafterdetachingtheloadedstring.Applications:Themainfunctionofaflywheelistomaintainanearlyconstantangularvelocityofthecrankshaft.Asmall
motorcanacceleratetheflywheelbetweenthepulses.Thephenomenonofprecessionhastobeconsideredwhenusingflywheelsinmovingvehicles.Flywheelsareusedinpunchingmachinesandrivetingmachines.ExperimentNo.15Objective:Todeterminethemomentofinertiaofaflywheel.Apparatus:Flywheel,weighthanger,slottedweights,
stopwatch,metrescale.Theory:Theflywheelconsistsofaheavycirculardisc/massivewheelfittedwithastrongaxleprojectingoneitherside.Theaxleismountedonballbearingsontwofixedsupports.Thereisasmallpegontheaxle.Oneendofacordislooselyloopedaroundthepeganditsotherendcarriestheweight-hanger.Let"m"bethe
massoftheweighthangerandhangingrings(weightassembly).Whenthemass"m"descendsthroughaheight"h",thelossinpotentialenergyisTheresultinggainofkineticenergyintherotatingflywheelassembly(flywheelandaxle)isWhereI-momentofinertiaoftheflywheelassemblyω-angularvelocityattheinstanttheweightassembly
touchestheground.Thegainofkineticenergyinthedescendingweightassemblyis,Wherevisthevelocityattheinstanttheweightassemblytouchestheground.TheworkdoneinovercomingthefrictionofthebearingssupportingtheflywheelassemblyisWheren-numberoftimesthecordiswrappedaroundtheaxleWf-workdonetoovercome
thefrictionaltorqueinrotatingtheflywheelassemblycompletelyonceThereforefromthelawofconservationofenergywegetOnsubstitutingthevalueswegetSignuptoviewthefulldocument!lock_openSignUpNowthekineticenergyoftheflywheelassemblyisexpendedinrotatingNtimesagainstthesamefrictionaltorque.ThereforeandIfr
istheradiusoftheaxle,thenvelocityvoftheweightassemblyisrelatedtorbytheequationSubstitutingthevaluesofvandWfweget:NowsolvingtheaboveequationforIWhere,I=MomentofinertiaoftheflywheelassemblyN=Numberofrotationoftheflywheelbeforeitstoppedm=massoftheringsn=Numberofwindingsofthestringon
theaxleg=Accelerationduetogravityoftheenvironment.analizador_sintacticamente_oraciones_subordinadas_online.pdfh=Heightoftheweightassemblyfromtheground.r=Radiusoftheaxle.Nowwebegintocountthenumberofrotations,NuntiltheflywheelstopsandalsonotethedurationoftimetforNrotation.Thereforewecan
calculatetheaverageangularvelocityinradianspersecond.SinceweareassumingthatthetensionalfrictionWfisconstantovertimeandangularvelocityissimplytwicetheaverageangularvelocitySignuptoviewthefulldocument!lock_openSignUpUnformattedAttachmentPreviewExperimentNo.15Objective:Todeterminethemomentof
inertiaofaflywheel.Apparatus:Flywheel,weighthanger,slottedweights,stopwatch,metrescale.Theory:Theflywheelconsistsofaheavycirculardisc/massivewheelfittedwithastrongaxleprojectingoneitherside.Theaxleismountedonballbearingsontwofixedsupports.buildingandstructuralsurveyingn6notespdfThereisasmallpegon
theaxle.Oneendofacordislooselyloopedaroundthepeganditsotherendcarriestheweight-hanger.Let"m"bethemassoftheweighthangerandhangingrings(weightassembly).Whenthemass"m"descendsthroughaheight"h",thelossinpotentialenergyisTheresultinggainofkineticenergyintherotatingflywheelassembly(flywheeland
axle)isWhereI-momentofinertiaoftheflywheelassemblyω-angularvelocityattheinstanttheweightassemblytouchestheground.Thegainofkineticenergyinthedescendingweightassemblyis,Wherevisthevelocityattheinstanttheweightassemblytouchestheground.Theworkdoneinovercomingthefrictionofthebearingssupportingthe
flywheelassemblyisWheren-numberoftimesthecordiswrappedaroundtheaxleWf-workdonetoovercomethefrictionaltorq...PurchasedocumenttoseefullattachmentUsergeneratedcontentisuploadedbyusersforthepurposesoflearningandshouldbeusedfollowingStudypool'shonorcode&termsofservice.Studypool4.7Trustpilot4.5
Sitejabber4.4Stuckonahomeworkquestion?Ourverifiedtutorscananswerallquestions,frombasicmathtoadvancedrocketscience!MOMENTOFINTERTIAOFAFLYWHEEL.EGERTONUNIVERSITYFACULTYOFENGINEERINGANDTECHNOLOGYDEPARTMENTOFINDUSTRIALANDENERGYENGINEERIGCOURSE:B.Sc.
MANUFACTURINGENGINEERING.COURSETITLE:MACHINEELEMENTS11.COURSECODE:MENT223.TASK:MOMENTOFINERTIAOFAFLYWHEEL.
NAME:KIPROTICHGARISON.REGNO.
B13/14411/16.DATEOFSUBMISSION:…26/07/2018.SIGN:………………………INSTRUCTOR:ENGR.VINCENTODHIAMBO.MOMENTOFINTERTIAOFAFLYWHEEL.
MOMENTOFINERTIAOFFLYWHEELObjectiveTheobjectiveofthisexperimentistodeterminetherelationshipbetweentheangularaccelerationofflywheelandthetorqueproducingtheacceleration.TheoryConsideringafallingmass,Netforce=mg-FAcceleration=aHencema=mg-maF=m(g-a)Providedthataismuchgreaterthang.F=mgFor
thewheel,Angulardisplacementϴ=2[.zonagum.pdf
]WhereN=Numberofrevolutions.Averagevelocity=12(ϴ+ωN)[rads/s]TimeforNrevolution=tseconds.
Therefore,Angulardisplacementϴ=12ωNtandωN=athenceϴ=12at2fromwhicha=42Accordingtothesecondlawofmotion,torqueproducingacceleration=MOMENTOFINTERTIAOFAFLYWHEEL.Fr=C=K.
42FromwhichK=24TheconstantofproportionalityKiscalledthemomentofinertiaandmaybecalculatedfromthedimensionsandmassoftheflywheel.K=I=ρπ2°22WhereR=Radiusofflywheelw=Widthofflywheelρ=Densityoftheflywheel=7850kg/m3PARAMETERS:Diameterofdisc=250mmDiameterofshaft=25mmWidthofdisc
=50mmDensityofplate=7850kg/m3Procedure1.Taketheloadhangerandpullingcordandhooktheendloopoverthepegontheflywheelshaft.2.Windupadefinitenumberofturns,say8,fromthepositionwherethecordloopfallsoffthepeg.